Solve this rudimentary calculus problem for lutz:

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If y=x²+x, then the derivative of y with respect to (1/1-x) is?

[Hiro]

w=t^f

[ME##]

Felt, I'm pretty sure there are only a few other people here who know calculus.


and I bet JMV will get it.

[Daddy]

use bbcode ;-;

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use bbcode ;-;

Not going to make it pretty at all.

[Det in F♯ Major]

y = det.

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y = det.

n

[Tomboh]

y = det/y
     

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y = det/y
     

N

[ME##]

y=det*y/clucky

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y=det*y/clucky

clucky= n = det
y=pqqu
rewritten:
pqqu=ny/n
pqqu=pqqu

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Let's put the verbal expression into a mathematical expression:
"differentiate y in respect to 1/(1-x)"
dy/d(1/(1-x))
Remember:
dy/du/[dx/du]=dy/dx; where u is a nonsensical expression

[guff]

for knowing so little about it you sure do talk about calculus a lot 

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for knowing so little about it you sure do talk about calculus a lot 

I KNOW I'M CONFUSED
how is it possible to differentiate in respect to a expression, as opposed to a variable

[Det in F♯ Major]

for knowing so little about it you sure do talk about calculus a lot 

GUFF WHAT'S YOUR MAJOR