MATH COMPETENCY TEST

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There are two different positive three-digit integers that are exactly forty-eight times the sum of their digits.  Find both three-digit positive integers that satisfy this condition.
Solve for possible luts.

[Wrench]

I can't open PDF's.

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I can't open PDF's.

oh

[Nyerp]

i think you mean calculus competency test

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i think you mean calculus competency test

mayb

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Thread updated to tax your bandwidth.

[Samus Aran]

not this shit again

MATH NEVER AGAIN

NEVER AGAIN

[Feynman]

The flawless integration of Preview in Safari is breathtaking.

[[REDACTED]]

not this shit again

MATH NEVER AGAIN

NEVER AGAIN

Honestly, it isn't that bad. You just have to use the first and second derivative tests.
Also, use sign graphs if you are confuzzled.

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Okay, I changed the problem.

[Samus Aran]

Honestly, it isn't that bad. You just have to use the first and second derivative tests.
Also, use sign graphs if you are confuzzled.

i know it's not hard, but i still hate it

[YPrrrr]

I'm not doing derivitives unless it's a matter of utmost importance. this does not meet that requirement

[Selkie]

fuck no.

[guff]

There are two different positive three-digit integers that are exactly forty-eight times the sum of their digits.  Find both three-digit positive integers that satisfy this condition.
Solve for possible luts.

boo, uninspired base-dependent problems 

anyways, 432 and 864

[Det in F♯ Major]

LOL FELT I GOT TEN POINTS EXTRA CREDIT IN MATH FOR HAVING YOU AND JMV SOLVE THIS PROBLEM FOR ME