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If y=x²+x, then the derivative of y with respect to (1/1-x) is?

w=t^f

Felt, I'm pretty sure there are only a few other people here who know calculus.


and I bet JMV will get it.

use bbcode ;-;

Quote from: Procyon lotor on November 15, 2008, 09:32:39 AM
use bbcode ;-;

Not going to make it pretty at all.

y = det.

Quote from: Detonator on November 15, 2008, 09:40:19 AM
y = det.

n

y = det/y
     

Quote from: Tomboh on November 15, 2008, 09:43:38 AM
y = det/y
     

N

y=det*y/clucky

Quote from: ME86 on November 15, 2008, 09:49:51 AM
y=det*y/clucky

clucky= n = det
y=pqqu
rewritten:
pqqu=ny/n
pqqu=pqqu

Let's put the verbal expression into a mathematical expression:
"differentiate y in respect to 1/(1-x)"
dy/d(1/(1-x))
Remember:
dy/du/[dx/du]=dy/dx; where u is a nonsensical expression

for knowing so little about it you sure do talk about calculus a lot  akudood;

Quote from: Commodore Guff on November 15, 2008, 11:56:35 AM
for knowing so little about it you sure do talk about calculus a lot  akudood;

I KNOW I'M CONFUSED
how is it possible to differentiate in respect to a expression, as opposed to a variable

Quote from: Commodore Guff on November 15, 2008, 11:56:35 AM
for knowing so little about it you sure do talk about calculus a lot  akudood;

GUFF WHAT'S YOUR MAJOR

Quote from: Ethereal on November 15, 2008, 12:00:32 PM
I KNOW I'M CONFUSED
how is it possible to differentiate in respect to a expression, as opposed to a variable

i'm not sure what that even means
ask your teacher for clarification

Quote from: Detonator on November 15, 2008, 12:03:39 PM
GUFF WHAT'S YOUR MAJOR

mathematics and statistics but i'm just in a community college so uh it's not very deep mathematics akudood;

Quote from: Commodore Guff on November 15, 2008, 05:02:47 PM
i'm not sure what that even means
ask your teacher for clarification
mathematics and statistics but i'm just in a community college so uh it's not very deep mathematics akudood;

You are ever so humble Sir Guff.