help me with physics

[strongbad]

i dont get this help me

Given the equation F=mv^2/R, what releationship exist between each of the following?
a. F and R
b. F and m
c. V and v

it is probably simple but idk i dont get it

i will probably post more stuff in this thread because this homework assignment is ugh

[The artist formally known]

That's like Newton's 2nd law in centripetal acceleration. It's less about physics and more about math.

F = force
m = mass
v = velocity
R = radius

Bold means vector. Where is big V?

[strongbad]

Oh for c. I meant F and v my bad. Yeah I understand what the units mean I just dont get how to say what their relationship is.

okay i also dont get

The graph of braking distnace versus car speed is part of a parabola. Thus, the equation  is written d=av^2+bv+c. The distance, d, has units in meters, and velocity, v, has units in meters/second. How could you find the units of a,b, and c? What would they be?

Also an easy question I think. As you can see I suck with variables.

[The artist formally known]

That question is worded pretty badly.

a. If F increases, what in the right hand equation must R do? R divides into (m x v^2) to create F. If F goes up, and (m x v^2) stays the same, then R must do what? R must go down or decrease. Do you see that there is an "inverse" relationship between R and F if (m x v^2) remains unchanged?

b. F and m: If F decreases and goes down, and v^2 and R remain unchanged, what must m do? Well, if F decreases, m must also decrease linearly, do you see that?

c. F and v: If F goes up, and m and R remain constant, how will v^2 react? F increases, v must also increase as well. But, because v is squared, it will increase as the "square" to F.

Let's say F = 2 and v = 3: If F increase by 1 to 3, then v increase by 4^2 = 16; if F increases by 1 again, v increases 5^2 or 25. Do you kind of see the "nonlinear" relationship there?

[strongbad]

Oh, I get it. Yeah I definitely see a non-linear relationship. Thanks man.

[The artist formally known]

Oh for c. I meant F and v my bad. Yeah I understand what the units mean I just dont get how to say what their relationship is.

okay i also dont get

The graph of braking distnace versus car speed is part of a parabola. Thus, the equation  is written d=av^2+bv+c. The distance, d, has units in meters, and velocity, v, has units in meters/second. How could you find the units of a,b, and c? What would they be?

Also an easy question I think. As you can see I suck with variables.

Here is the start of it, figure out the rest.

(meters) = a(meters/second)² + b(meters/second) + c

[strongbad]

So are a, b, and c, just predeterminded variables that shape the equation? I am familiar with the quadratic equation, so a, b, and c must just be there to shape the parabola?