def isPandigital(n):
digList = list(str(n))
for i in digList:
if str(i) in digList:
continue
else:
return False
return max(digList) == len(str(n))
print isPandigital(3142)
Keeps returning False. HOWEVER
def isPandigital(n):
digList = list(str(n))
for i in digList:
if str(i) in digList:
continue
else:
return False
return max(digList)
print isPandigital(3142)
Will return 4
and
def isPandigital(n):
digList = list(str(n))
for i in digList:
if str(i) in digList:
continue
else:
return False
return len(str(n))
print isPandigital(3142)
Also returns 4, which both are correct.
So I don't get why it returns false, because if you have the == isn't it the same as saying:
return 4 == 4, which would be true?
ffffffffffff
Did you set it to Wumbo?
Quote from: Bassir on March 06, 2009, 06:18:37 PM
Did you set it to Wumbo?
I Wumbo, you wumbo, he, she, me, wumbo, wumbo, wumboing, I'll have three wumbo, wumbora, wumbology, the study of wumbo? It's first grade, JMV! bassir;
Quote from: Raekewn on March 06, 2009, 05:05:53 PM
def isPandigital(n):
digList = list(str(n))
for i in digList:
if str(i) in digList:
continue
else:
return False
return max(digList) == len(str(n))
print isPandigital(3142)
what the lol how is that testing if it's pandigital
all that for loop is doing is checking to see if each element of digList is an element of digList, which is obviously true
also, there's not really a reason to make digList a list because strings are iterable too
and the reason that it returns false is that you're comparing a string ("4") to an int (4) which will always evaluate to false
but basically if you actually want to test for pandigitalness then you've got to generate a list of the numbers from 1 to n (range(1, n + 1)), then check to see if each digit of your input is in that list and that the lengths are the same baddood;