help

[?????]

doesn't work like that bro

log(y) = log₁₀(y)
lob_b(y)=x

log(x + 8) = 1 - log(x - 7)
10^(x+8)=1-10^(x-7)

Why can't it be rewritten like that?

[Nyerp]

log(y) = log₁₀(y)
lob_b(y)=x

log(x + 8) = 1 - log(x - 7)
10^(x+8)=1-10^(x-7)

Why can't it be rewritten like that?

lob_b(y)=x

to change that to an exponential equation, it's b^x=y, not whatever the hell you just did

you also can't switch to exponential in this case until you combine the logs

so there

[[REDACTED]]

holy shit. nyerp is right.

[Nyerp]

holy shit. nyerp is right.

what

also answer my other question!! plz

[[REDACTED]]

oh wow i completely ignored the fact that log₇(49) is perfectly solvable

now do this fuck felty:

log(x + 8) = 1 - log(x - 7)

me too

[spoiler]it was actually 4 months ago in high school where i actually learned things >:[[/spoiler]

<=>log(x+8)=log(10)-log(x-7)
<=>log(x+8)=log(10/(x-7))
<=>x+8=10/(x-7)
(x+8)(x-7)=10
x^2+x-56=10
x^2+x-66=0
use quad. formula.

[Nyerp]

i found the problem i was having

[spoiler]i had read the quadratic formula wrong lol [/spoiler]

thanks

but stick around cuz i might need more help

[Nyerp]

log(x³) = (log(x))²

where did you gooooooooooo

[[REDACTED]]

log(x³) = (log(x))²

where did you gooooooooooo

3log(x)=(log(x))². Let u=log(x). then 3u=u³. u=0, -sprt(3), sqrt(3). Find the extraneous roots and don't take them into consideration. Find x for each possible u.

[Nyerp]

just give me the highest zero

ALSO WHAT THE FUCK DOES THE LEWIS STRUCTURE OF A HYPONITRITE ION LOOK LIKE

[Kalahari Inkantation]

cjlubdoods;

[Nyerp]

my answer was right already but lol thanks cjlubdoods;

[[REDACTED]]

I borked that up. u^2-3u=0. u=0,3

[Nyerp]

so the zeros are 1 and 1000

yay i got it right

thanks

[Classic]

I hate math.